sample case study questions and answers class 9

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CBSE Class 9 Mathematics Case Study Questions

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Significance of Mathematics in Class 9

Mathematics is an important subject for students of all ages. It helps students to develop problem-solving and critical-thinking skills, and to think logically and creatively. In addition, mathematics is essential for understanding and using many other subjects, such as science, engineering, and finance.

CBSE Class 9 is an important year for students, as it is the foundation year for the Class 10 board exams. In Class 9, students learn many important concepts in mathematics that will help them to succeed in their board exams and in their future studies. Therefore, it is essential for students to understand and master the concepts taught in Class 9 Mathematics .

Case studies in Class 9 Mathematics

A case study in mathematics is a detailed analysis of a particular mathematical problem or situation. Case studies are often used to examine the relationship between theory and practice, and to explore the connections between different areas of mathematics. Often, a case study will focus on a single problem or situation and will use a variety of methods to examine it. These methods may include algebraic, geometric, and/or statistical analysis.

Example of Case study questions in Class 9 Mathematics

The Central Board of Secondary Education (CBSE) has included case study questions in the Class 9 Mathematics paper. This means that Class 9 Mathematics students will have to solve questions based on real-life scenarios. This is a departure from the usual theoretical questions that are asked in Class 9 Mathematics exams.

The following are some examples of case study questions from Class 9 Mathematics:

Class 9 Mathematics Case study question 1

There is a square park ABCD in the middle of Saket colony in Delhi. Four children Deepak, Ashok, Arjun and Deepa went to play with their balls. The colour of the ball of Ashok, Deepak,  Arjun and Deepa are red, blue, yellow and green respectively. All four children roll their ball from centre point O in the direction of   XOY, X’OY, X’OY’ and XOY’ . Their balls stopped as shown in the above image.

Answer the following questions:

Answer Key:

Class 9 Mathematics Case study question 2

• Now he told Raju to draw another line CD as in the figure
• The teacher told Ajay to mark  ∠ AOD  as 2z
• Suraj was told to mark  ∠ AOC as 4y
• Clive Made and angle  ∠ COE = 60°
• Peter marked  ∠ BOE and  ∠ BOD as y and x respectively

Now answer the following questions:

• 2y + z = 90°
• 2y + z = 180°
• 4y + 2z = 120°
• (a) 2y + z = 90°

Class 9 Mathematics Case study question 3

• (a) 31.6 m²
• (c) 513.3 m³
• (b) 422.4 m²

Class 9 Mathematics Case study question 4

How to Answer Class 9 Mathematics Case study questions

To crack case study questions, Class 9 Mathematics students need to apply their mathematical knowledge to real-life situations. They should first read the question carefully and identify the key information. They should then identify the relevant mathematical concepts that can be applied to solve the question. Once they have done this, they can start solving the Class 9 Mathematics case study question.

Students need to be careful while solving the Class 9 Mathematics case study questions. They should not make any assumptions and should always check their answers. If they are stuck on a question, they should take a break and come back to it later. With some practice, the Class 9 Mathematics students will be able to crack case study questions with ease.

Class 9 Mathematics Curriculum at Glance

At the secondary level, the curriculum focuses on improving students’ ability to use Mathematics to solve real-world problems and to study the subject as a separate discipline. Students are expected to learn how to solve issues using algebraic approaches and how to apply their understanding of simple trigonometry to height and distance problems. Experimenting with numbers and geometric forms, making hypotheses, and validating them with more observations are all part of Math learning at this level.

The suggested curriculum covers number systems, algebra, geometry, trigonometry, mensuration, statistics, graphing, and coordinate geometry, among other topics. Math should be taught through activities that include the use of concrete materials, models, patterns, charts, photographs, posters, and other visual aids.

CBSE Class 9 Mathematics (Code No. 041)

Class 9 Mathematics question paper design

The CBSE Class 9 mathematics question paper design is intended to measure students’ grasp of the subject’s fundamental ideas. The paper will put their problem-solving and analytical skills to the test. Class 9 mathematics students are advised to go through the question paper pattern thoroughly before they start preparing for their examinations. This will help them understand the paper better and enable them to score maximum marks. Refer to the given Class 9 Mathematics question paper design.

QUESTION PAPER DESIGN (CLASS 9 MATHEMATICS)

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Class 9 is an important milestone in a student’s life. It is the last year of high school and the last chance to score well in the CBSE board exams. myCBSEguide is the perfect platform for students to get started on their preparations for Class 9 Mathematics. myCBSEguide provides comprehensive study material for all subjects, including practice questions, sample papers, case study questions and mock tests. It also offers tips and tricks on how to score well in exams. myCBSEguide is the perfect door to enter for class 9 CBSE preparations.

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14 thoughts on “CBSE Class 9 Mathematics Case Study Questions”

This method is not easy for me

aarti and rashika are two classmates. due to exams approaching in some days both decided to study together. during revision hour both find difficulties and they solved each other’s problems. aarti explains simplification of 2+ ?2 by rationalising the denominator and rashika explains 4+ ?2 simplification of (v10-?5)(v10+ ?5) by using the identity (a – b)(a+b). based on above information, answer the following questions: 1) what is the rationalising factor of the denominator of 2+ ?2 a) 2-?2 b) 2?2 c) 2+ ?2 by rationalising the denominator of aarti got the answer d) a) 4+3?2 b) 3+?2 c) 3-?2 4+ ?2 2+ ?2 d) 2-?3 the identity applied to solve (?10-?5) (v10+ ?5) is a) (a+b)(a – b) = (a – b)² c) (a – b)(a+b) = a² – b² d) (a-b)(a+b)=2(a² + b²) ii) b) (a+b)(a – b) = (a + b

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CBSE Class 9th Maths 2023 : 30 Most Important Case Study Questions with Answers; Download PDF

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CBSE Class 9 Maths exam 2022-23 will have a set of questions based on case studies in the form of MCQs. CBSE Class 9 Maths Question Bank on Case Studies given in this article can be very helpful in understanding the new format of questions.

Each question has five sub-questions, each followed by four options and one correct answer. Students can easily download these questions in PDF format and refer to them for exam preparation.

CBSE Class 9 All Students can also Download here Class 9 Other Study Materials in PDF Format.

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CBSE Class 9 Maths Most Important Case Study Based Questions With Solution

Cbse class 9 mathematics case study questions.

In this post I have provided CBSE Class 9 Maths Case Study Based Questions With Solution. These questions are very important for those students who are preparing for their final class 9 maths exam.

All these questions provided in this article are with solution which will help students for solving the problems. Dear students need to practice all these questions carefully with the help of given solutions.

As you know CBSE Class 9 Maths exam will have a set of cased study based questions in the form of MCQs. CBSE Class 9 Maths Question Bank given in this article can be very helpful in understanding the new format of questions for new session.

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Case studies in class 9 mathematics.

The Central Board of Secondary Education (CBSE) has included case study based questions in the Class 9 Mathematics paper in current session. According to new pattern CBSE Class 9 Mathematics students will have to solve case based questions. This is a departure from the usual theoretical conceptual questions that are asked in Class 9 Maths exam in this year.

Each question provided in this post has five sub-questions, each followed by four options and one correct answer. All CBSE Class 9th Maths Students can easily download these questions in PDF form with the help of given download Links and refer for exam preparation.

There is many more free study materials are available at Maths And Physics With Pandey Sir website. For many more books and free study material all of you can visit at this website.

Given Below Are CBSE Class 9th Maths Case Based Questions With Their Respective Download Links.

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CBSE Class 9 Science Important Case Study Questions with Answers for Term 2 Exam 2022 (PDF)

Check important case study questions of cbse class 9 science to prepare for the cbse term 2 exam 2022. all these questions have been put together by subject experts..

CBSE Class 9 Term 2 Exam 2022:  Important case based questions for CBSE Class 9 Science are provided here students to prepare for the upcoming Term 2 Exam 2022. All the questions provided below are curated by the subject experts. These questions are really helpful to revise important concepts and prepare the case study questions for the exam. Answers to all questions have been provided for reference. So, students should practice the chapter-wise questions to clearly understand the right way to attempt the case based questions. Download the chapter-wise questions in PDF.

Check some of the important case study questions below:

Q. Read the following and answer the questions :

A student was asked by his teacher to verify the law of conservation of mass in the laboratory. He prepared 5% aqueous solutions of NaCl and Na 2 SO 4 . He mixed 10 mL of both these solutions in a conical flask. He weighed the flask on a balance. He then stirred the flask with a rod and weighed it after sometime. There was no change in mass.

• Was the student able to verify the law of conservation of mass?
• If not, what was the mistake committed by him?
• In your opinion, what he should have done?
• What is the molar mass of Na 2 SO 4 ?
• No, he could not verify the law of conservation of mass in-spite of the fact that there was no change in mass.
• No chemical reaction takes place between NaCl and Na 2 SO 4 . This means that no reaction actually took place in the flask.
• He should have performed the experiment by using aqueous solutions of BaCl 2 and Na 2 SO 4 . A chemical reaction takes place in this case and a white precipitate of BaSO 4 is formed.
• Will the weight of the precipitate be the same as that of the reactants before mixing?
• If not, what she should have done?
• Which law of chemical combination does this support?
• State the law of conservation of mass.
• No, it will not be the same.
• She should have weighed the total contents of the beaker after the reaction and not the precipitate alone.
• It supports the law of conservation of mass.
• Mass can neither be created nor destroyed during a chemical reaction.

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CBSE Case Study Questions Class 9 Maths Chapter 12 Heron’s Formula PDF Download

CBSE Case Study Questions Class 9 Maths Chapter 12  are very important to solve for your exam. Class 9 Maths Chapter 12 Case Study Questions have been prepared for the latest exam pattern. You can check your knowledge by solving  case study-based   questions for Class 9 Maths Chapter 12  Heron’s Formula

Case Study Questions Class 9 Maths Chapter 12

Case Study 1: A group of students is learning about Heron’s Formula for finding the area of a triangle. They encountered the following scenario:

Rohan and Kavya came across a triangular field in their village. They made the following observations:

• The lengths of the three sides of the triangular field are 8 meters, 12 meters, and 15 meters.
• The perimeter of the triangular field is 35 meters.

Based on this information, the students were asked to apply Heron’s Formula to find the area of the triangular field. Let’s see if you can answer the questions correctly:

MCQ Questions:

Q1. The semiperimeter of the triangular field is: (a) 8 meters (b) 12 meters (c) 15 meters (d) 17.5 meters

Answer: (d) 17.5 meters

Q2. Using Heron’s Formula, the area of the triangular field is: (a) 24 square meters (b) 30 square meters (c) 36 square meters (d) 40 square meters

Answer: (b) 30 square meters

Q3. The type of triangle formed by the sides of the field is: (a) Equilateral (b) Isosceles (c) Scalene (d) Right-angled

Answer: (c) Scalene

Q4. The length of the altitude corresponding to the side of 15 meters is: (a) 2 meters (b) 4 meters (c) 6 meters (d) 8 meters

Answer: (c) 6 meters

Q5. The lengths of the altitudes corresponding to the sides of 8 meters and 12 meters are: (a) 4 meters and 6 meters (b) 6 meters and 8 meters (c) 8 meters and 10 meters (d) 10 meters and 12 meters

Answer: (a) 4 meters and 6 meters

Case Study 2: A group of students is studying Heron’s Formula for finding the area of a triangle. They encountered the following scenario:

Neha and Mohan went on a field trip to a riverbank. They noticed a triangular piece of land that they wanted to measure and calculate its area. They made the following observations:

• Neha measured the lengths of the three sides of the triangular piece of land as 7 meters, 9 meters, and 11 meters.
• Mohan measured the lengths of the three sides of the same triangular piece of land as 10 meters, 12 meters, and 15 meters.

Based on this information, the students were asked to apply Heron’s Formula to find the area of the triangular piece of land. Let’s see if you can answer the questions correctly:

Q1. Using Neha’s measurements, the semiperimeter of the triangular piece of land is: (a) 13 meters (b) 16 meters (c) 19 meters (d) 23 meters

Answer: (c) 19 meters

Q2. Using Neha’s measurements, the area of the triangular piece of land is: (a) 24 square meters (b) 26 square meters (c) 28 square meters (d) 30 square meters

Answer: (a) 24 square meters

Q3. Using Mohan’s measurements, the semiperimeter of the triangular piece of land is: (a) 16 meters (b) 18 meters (c) 21 meters (d) 25 meters

Answer: (c) 21 meters

Q4. Using Mohan’s measurements, the area of the triangular piece of land is: (a) 40 square meters (b) 42 square meters (c) 45 square meters (d) 48 square meters

Answer: (b) 42 square meters

Q5. The measurements taken by Neha represent a triangle that is: (a) Equilateral (b) Isosceles (c) Scalene (d) Right-angled

Hope the information shed above regarding Case Study and Passage Based Questions for Case Study Questions Class 9 Maths Chapter 12 Heron’s Formula with Answers Pdf free download has been useful to an extent. If you have any other queries about Case Study Questions Class 9 Maths Chapter 12 Heron’s Formula and Passage-Based Questions with Answers, feel free to comment below so that we can revert back to us at the earliest possible.

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Case Study Questions Class 9 Science The Fundamental Unit of Life

Case study questions class 9 science chapter 5 the fundamental unit of life.

CBSE Class 9 Case Study Questions Science The Fundamental Unit of Life. Important Case Study Questions for Class 9 Exam. Here we have arranged some Important Case Base Questions for students who are searching for Paragraph Based Questions The Fundamental Unit of Life.

At Case Study Questions there will given a Paragraph. In where some Questions will made on that respective Case Based Study. There will various types of marks will given 1 marks, 2 marks, 3 marks or 4 marks.

CBSE Case Study Questions Class 9 Science – The Fundamental Unit of Life

All living Organisms are made up of cells and these cells perform all the functions essential for the survival of the Organism eg. Respiration, digestion, excretion etc. In Unicellular organisms, a single cell carries out all these functions and in multicellular organisms different group of cells carry out different functions.

Cells were first discovered by Robert Hooke in 1665. He observed the cells in a cork slice with the help of a primitive microscope. Leeuwenhoek (1674), with the improved microscope, discovered the free living cells in pond water for the first time. It was Robert Brown in 1831 who discovered the nucleus in the cell. Purkinje in 1839 coined the term ‘protoplasm’ for the fluid substance of the cell.

(1) Who discovered the cell?

(a) Robert Hooke

(b) Leeuwenhoek

(c) Robert Brown

(d) T. Schwann

(2) Who discovered the nucleus in the cell?

(3) Who coined the term ‘Protoplasm’?

(d) Purkinje

(4) What is protoplasm?

(a) Unit of life

(b) Cell organelle

(c) Fluid substance of the cell.

(d) Cytoplasm

(5) Which of these statement is true about the cell?

(a) All organism are made up of cell

(b) Cell is the basic unit of life

(c) Cell is responsible for different metabolic functions

(d) All above

The cell theory, that all the plants and animals are composed of cells and that the cell is the basic unit of life, was presented by two biologists, German zoologist Schleiden (1838) and British zoologist Schwann (1839). The cell theory was further expanded by Virchow (1855) by suggesting that all cells arise from pre-existing cells. With the discovery of the electron microscope in 1940, it was possible to observe and understand the complex structure of the cell and its various organelles.

(1) Theodore Schwann was a _____

(a) British zoologist

(b) German zoologist

(c) British botanist

(d) German botanist

(2) Matthias Schleiden was a _____

(a) German zoologist

(b) British zoologist

(c) German botanist

(d) British botanist

(3) Which of these scientists formulated the cell theory?

(a) Schleiden and Schwann

(b) Rudolf Virchow

(c) Robert Koch

(d) Antony Von Leeuwenhoek

(4) Which scientist was the first to explain that new cells arise from pre-existing cells?

(a) Antony Von Leeuwenhoek

(b) Matthias Schleiden

(c) Rudolph Virchow

(d) Theodore Schwann

(5) Which of these scientists did not contribute to the cell theory?

(a) Robert Koch

(c) Theodore Schwann

(d) Rudolph Virchow

Plasma membrane or Cell membrane is the outermost covering of the cell that separates the contents of the cell from its external environment. The plasma membrane is flexible and is made up of organic molecules called lipids and proteins. The flexibility of the cell membrane also enables the cell to engulf in food and other material from its external environment. Such processes are known as endocytosis.The plasma membrane allows or permits the entry and exit of some materials in and out of the cell. It also prevents movement of some other materials. The cell membrane, therefore, is called a selectively permeable membrane.

Some substances like carbon dioxide or oxygen can move across the cell membrane by a process called diffusion. There is spontaneous movement of a substance from a region of high concentration to a region where its concentration is low. Similar thing happens in cells – some substance like CO2 (carbon dioxide is cellular waste and requires to be excreted out by the cell) accumulates in high concentrations inside the cell. In the cell’s external environment, the concentration of CO2 is low as compared to that inside the cell. As soon as there is a difference of concentration of CO2 inside and outside a cell, CO2 moves out of the cell, from a region of high concentration, to a region of low concentration outside the cell by the process of diffusion.

Water obeys the law of diffusion. The movement of water molecules through such a selectively permeable membrane is called osmosis. The movement of water across the plasma membrane is also affected by the amount of substance dissolved in water. Thus, osmosis is the net diffusion of water across a selectively permeable membrane toward a higher solute concentration.

(1) The plasma membrane is made up of ___________

(a) Proteins

(c) Proteins and Lipids (Lipoproteins)

(d) none of above

(2) Which of the following substance is known as cellular waste?

(b) Nitrogen

(c) Carbon dioxide

(d) None of above

(3) The movement of a substance from the region of higher concentration to the region where its concentration is lower is called as _____________

(a) Osmosis

(b) Diffusion

(c) Excretion of CO2 (carbon dioxide)

(4) Why cell membrane is known as selectively permeable membrane?

(5) What is mean by diffusion?

(6) Define Osmosis.

(d) Cell membrane allows or permits the entry and exit of some materials in and out of the cell. It also prevents movement of some other materials. Hence it is called as selectively permeable membrane.

(e) It is spontaneous movement of a substance from a region of high concentration to a region where its concentration is low. For example, some substances like carbon dioxide or oxygen can move across the cell membrane by a process called diffusion.

Plant cells, in addition to the plasma membrane, have another rigid outer covering called the cell wall. The cell wall lies outside the plasma membrane. The plant cell wall is mainly composed of cellulose. Cellulose is a complex substance and provides structural strength to plants. When a living plant cell loses water through osmosis there is shrinkage or contraction of the contents of the cell away from the cell wall. This phenomenon is known as plasmolysis.

(1) Which of the following is the main constituent of cell wall?

(c) Lipoproteins

(d) Cellulose

(2) Which of the following is outer most covering of the plant cell?

(a) Cell membrane

(b) Plasma membrane

(c) Cell wall

(3) Choose the correct set of statements from the following.

Statement 1 – Cell wall lies outside the plasma membrane.

Statement 2 – Cell wall is mainly composed of cellulose.

Statement 3 – Cellulose is a complex substance and provides structural strength to plants.

Statement 4 – Cell wall lies outside the plasma membrane.

(a) Statement 1 & 3

(b) Statement 1 & 2

(c) Statement 3 & 4

(d) All statement are correct

(4) What is mean by plasmolysis?

(5) What is the reason behind structural strength of plant cell?

(4) When living plant cell loses water through osmosis there is contraction of the contents of the cell away from the cell wall. This phenomenon is called as plasmolysis.

(5) The plant cell wall is mainly composed of cellulose. Cellulose is a complex substance and provides structural strength to plants.

Every cell has a membrane around it to keep its own contents separate from the external environment. Large and complex cells, including cells from multicellular organisms, need a lot of chemical activities to support their complicated structure and function. To keep these activities of different kinds separate from each other, these cells use membrane-bound little structures within themselves. The cytoplasm is the jelly like fluid content inside the plasma membrane which contains many specialised cell organelles. Such as Endoplasmic Reticulum, Golgi apparatus, Lysosomes, Ribosomes, Nucleus, Chloroplast, Mitochondria and Plastids.Each of these organelles performs a specific function for the cell. Some of these organelles are visible only with an electron microscope. They are important because they carry out some very crucial functions in cells.

(1) Identify the statement which is true for cells.

Statement 1 – Some cell organelles are visible only with an electron microscope.

Statement 2 – Cytoplasm is jelly like fluid present inside the cell.

Statement 3 – Cell organelles perform all the functions in cell.

Statement 4 – Every cell has a membrane around it to keep its own contents separate from the external environment.

(b) Statement 2 & 4

(c) Statement 1 & 4

(d) All statement are true.

(2) A suitable term for the various components of cells is ________

(b) cell organelles

(c) chromosomes

(3) The jelly-like fluid substance present in cells is called __________

(a) Protoplasm

(b) Chromosome

(c) Chloroplast

(4) What is cell organelles?

(5) Enlist the any five cell organelles.

(4) Cell organelles are the specialized organelles present with in the cells these organelles are involved in carrying out essential functions.

(5) Endoplasmic Reticulum, Golgi apparatus, Lysosomes, Ribosomes, Nucleus, Chloroplast, Mitochondria and Plastids.

The endoplasmic reticulum is a large network of membrane-bound tubes and sheets. It looks like long tubules or round or oblong bags (vesicles). It is discovered by Porter and Thompson.  The ER membrane is similar in structure to the plasma membrane. There are two types of ER– rough endoplasmic reticulum (RER) and smooth endoplasmic reticulum (SER). RER looks rough under a microscope because it has particles called ribosomes attached to its surface. The ribosomes, which are present in all active cells, are the sites of protein manufacture. The manufactured proteins are then sent to various places in the cell depending on need, using the ER. The SER helps in the manufacture of fat molecules, or lipids, important for cell function. Some of these proteins and lipids help in building the cell membrane. This process is known as membrane biogenesis. Some other proteins and lipids function as enzymes and hormones. Although the ER varies greatly in appearance in different cells, it always forms a network system.

(1) Who discovered endoplasmic reticulum?

(a) Porter and Thompson

(b) Robert Brown

(c) Robert Hooke

(d) Koshland

(2) Which are the components of endoplasmic reticulum__________

(a) Cisternae, tubules and vesicles.

(b) Cisternae, chromatids and vacuoles

(c) Both a and b

(d) None of the above

(3) Endoplasmic reticulum membrane which is associated with ribosomes is called_______

(a) ER lumen

(b) Smooth endoplasmic reticulum

(c) Rough endoplasmic reticulum

(d) Endosome

(4) Enlist the types of Endoplasmic Reticulum.

(5) Define membrane biogenesis?

(4) Smooth endoplasmic reticulum and Rough endoplasmic reticulum

(5) The SER helps in the manufacture of fat molecules, or lipids, important for cell function. Some of these proteins and lipids help in building the cell membrane. This process is known as membrane biogenesis.

The Golgi apparatus, first described by Camilo Golgi, consists of a system of membrane-bound vesicles (flattened sacs) arranged approximately parallel to each other in stacks called cisterns. These membranes often have connections with the membranes of ER and therefore constitute another portion of a complex cellular membrane system. The material synthesised near the ER is packaged and dispatched to various targets inside and outside the cell through the Golgi apparatus. Its functions include the storage, modification and packaging of products in vesicles. In some cases, complex sugars may be made from simple sugars in the Golgi apparatus. The Golgi apparatus is also involved in the formation of lysosomes

(d) Camilo Golgi

(2) A system of membrane-bound flattened sacs arranged approximately parallel to each other in stacks are called as _________

(a) Cisterns

(b) Vesicles

(c) Golgi complex

(d) Vacuoles

(3) Membrane bound flattened sacs is termed as _________

(4) Enlist the function of Golgi apparatus.

(5) Name the cell organelles which is involved in the formation of lysosomes?

(4) Functions of Golgi apparatus:

• Storage, modification and packaging of products
• Involved in formation of lysosomes

(5) Golgi apparatus

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Ok Dibya, We will design this page

tomorrow is my science final papper. this case study is come in my papper than i am very happy.

This very helpful casebased questions Thanku for this

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Class 9 Maths Case Study Questions of Chapter 10 Circles PDF Download

• Post author: studyrate
• Post published:
• Post category: class 9th
• Post comments: 3 Comments

Case study Questions in Class 9 Mathematics Chapter 10  are very important to solve for your exam. Class 9 Maths Chapter 10 Case Study Questions have been prepared for the latest exam pattern. You can check your knowledge by solving case study-based questions for Class 9 Maths Case Study Questions Chapter 10 Circles

Join our Telegram Channel, there you will get various e-books for CBSE 2024 Boards exams for Class 9th, 10th, 11th, and 12th.

These case study questions challenge students to apply their knowledge of quadrilaterals in practical scenarios, enhancing their problem-solving abilities. This article provides the Class 9 Maths Case Study Questions of Chapter 10 Circles, enabling students to practice and excel in their examinations.

Circles Case Study Questions With Answers

Here, we have provided case-based/passage-based questions for Class 9 Maths Chapter 10 Circles

Case Study/Passage-Based Questions

Case Study 2: Three friends Amit, Mayank, and Richa were playing with the ball by standing in a circle at A, B, and C points respectively. Richa throws a ball to Amit, Amit to Mayank, and Mayank to Richa. They all are equidistant from each other as shown in the figure.

Considering O as the centere of the circle, answer the following questions

Which type of ▲ABC is given in figure? (a) Right angled triangle (b) Equilateral triangle (c) Isosceles triangle (d) Scalene triangle

Answer: (b) Equilateral triangle

Measure of ∠ABC is (a) 45° (b) 60° (c) 30° (d) 90°

Answer: (b) 60°

If AB = 6 cm, then BC + CA is equal to (a) 12 cm (b) 14 cm (c) 15 cm (d) 18 cm

Answer: (a) 12 cm

Measure of ∠BOC is (a) 90° (b) 100° (c) 120° (d) 150°

Answer: (c) 120°

Value of ∠OBC + ∠OCB is (a) 30° (b) 45° (c) 90° (d) 60°

Answer: (d) 60°

Case Study 2: Rohan is a class 9th student. He did not attend school as his health is not fine for a few days. At home, he opens his Maths textbook and observes chapter circles. He was so much curious to know about the properties of circles. His father Mr. Raman, who is also a good Mathematician helps Rohan to understand all properties one by one. At last, he asks some questions to Rohan for quick revision. Help Rohan to answer the following questions.

A circle can circumscribe a (a) Rectangle (b) Trapezium (c) Triangle (d) All of these

Answer: (d) All of these

The perpendicular distance from the centre of the circle decreases when (a) the length of the chord increases (b) the length of the chord decreases (c) Radius of circle is decreased (d) Radius of circle is increased

Answer: (a) the length of the chord increases

The number of radii that can be drawn in a circle is (a) 10 (b) 100 (c) 1000 (d) infinite

Answer: (d) infinite

The distance from the centre of the circle to the longest chord is equal to (a) 22/7 units (b) 0 unit (c) 1 unit (d) 3 units

Answer: (b) 0 unit

Angle formed by the equal arcs on the circumference of the circle (a) are supplementary (b) are equal (c) are complimentary (d) None of these

Answer: (b) are equal

Hope the information shed above regarding Case Study and Passage Based Questions for Class 9 Mathematics Chapter 10 Circles with Answers Pdf free download has been useful to an extent. If you have any other queries about CBSE Class 9 Maths Circles Case Study and Passage Based Questions with Answers, feel free to comment below so that we can revert back to us at the earliest possible By Team Study Rate

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• CBSE Maths Important Questions
• Class 9 Maths
• Chapter 6: Lines Angles

Important Questions CBSE Class 9 Maths Chapter 6-Lines and Angles

CBSE Class 9 Maths Chapter 6 (Lines and Angles) Important Questions with solutions are given here, which can be easily accessed. These questions have been prepared by our experts for students of standard 9 to make them prepare for final exam (2022 – 2023) . All the questions are based on CBSE syllabus and taken in reference from NCERT book. Students can do their revision by practising the Important Questions for CBSE Class 9 Maths Chapter 6: Lines and Angles here and score good marks.

To revise the important questions chapter-wise for 9th Maths , reach us at BYJU’S. The chapter lines and angles will consist of topics such as angles formed after the intersection of two lines, linear pair of angles, complementary angles, etc. Let us solve the questions here to understand all the concepts.

Also Check:

• Important 2 Marks Questions for CBSE 9th Maths
• Important 3 Marks Questions for CBSE 9th Maths
• Important 4 Marks Questions for CBSE 9th Maths

Important Questions & Solutions For Class 9 Chapter 6 (Lines and Angles)

Q.1: In the figure, lines AB and CD intersect at O. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

From the given figure, we can see;

∠AOC, ∠BOE, ∠COE and ∠COE, ∠BOD,  ∠BOE form a straight line each.

So, ∠AOC + ∠BOE +∠COE = ∠COE +∠BOD + ∠BOE = 180°

Now, by substituting the values of ∠AOC + ∠BOE = 70° and ∠BOD = 40° we get:

70° +∠COE = 180°

∠COE = 110°

110° +  40° + ∠BOE = 180°

Q.2: In the Figure, lines XY and MN intersect at O. If ∠POY = 90° and a : b = 2 : 3, find c.

As we know, the sum of the linear pair is always equal to 180°

∠POY + a + b = 180°

Substituting the value of ∠POY = 90° (as given in the question) we get,

a + b = 90°

Now, it is given that a : b = 2 : 3 so,

Let a be 2x and b be 3x.

∴ 2x + 3x = 90°

Solving this we get

So, x = 18°

∴ a = 2 × 18° = 36°

Similarly, b can be calculated and the value will be

b = 3 × 18° = 54°

From the diagram, b + c also forms a straight angle so,

b + c = 180°

=> c + 54° = 180°

Q.3: In the Figure, POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that ∠ROS = 1/2(∠QOS – ∠POS).

In the question, it is given that (OR ⊥ PQ) and ∠POQ = 180°

So, ∠POS + ∠ROS + ∠ROQ = 180°    (Linear pair of angles)

Now, ∠POS + ∠ROS = 180° – 90°      (Since ∠POR = ∠ROQ = 90°)

∴ ∠POS + ∠ROS = 90°

Now, ∠QOS = ∠ROQ + ∠ROS

It is given that ∠ROQ = 90°,

∴ ∠QOS = 90° + ∠ROS

Or, ∠QOS – ∠ROS = 90°

As ∠POS + ∠ROS = 90° and ∠QOS – ∠ROS = 90°, we get

∠POS + ∠ROS = ∠QOS – ∠ROS

=>2 ∠ROS + ∠POS = ∠QOS

Or, ∠ROS = ½ (∠QOS – ∠POS) (Hence proved).

Q.4: It is given that ∠XYZ = 64° and XY is produced to point P. Draw a figure from the given information. If ray YQ bisects ∠ZYP, find ∠XYQ and reflex ∠QYP.

Here, XP is a straight line

So, ∠XYZ +∠ZYP = 180°

substituting the value of ∠XYZ = 64° we get,

64° +∠ZYP = 180°

∴ ∠ZYP = 116°

From the diagram, we also know that ∠ZYP = ∠ZYQ + ∠QYP

Now, as YQ bisects ∠ZYP,

∠ZYQ = ∠QYP

Or, ∠ZYP = 2∠ZYQ

∴ ∠ZYQ = ∠QYP = 58°

Again, ∠XYQ = ∠XYZ + ∠ZYQ

By substituting the value of ∠XYZ = 64° and ∠ZYQ = 58° we get.

∠XYQ = 64° + 58°

Or, ∠XYQ = 122°

Now, reflex ∠QYP = 180° + ∠XYQ

We computed that the value of ∠XYQ = 122°. So,

∠QYP = 180° + 122°

∴ ∠QYP = 302°

Q.5: In the Figure, if AB || CD, EF ⊥ CD and ∠GED = 126°, find ∠AGE, ∠GEF and ∠FGE .

Since AB || CD GE is a transversal.

It is given that ∠GED = 126°

So, ∠GED = ∠AGE = 126° (alternate interior angles)

∠GED = ∠GEF + ∠FED

EF ⊥ CD, ∠FED = 90°

∴ ∠GED = ∠GEF + 90°

Or, ∠GEF = 126° – 90° = 36°

Again, ∠FGE + ∠GED = 180° (Transversal)

Substituting the value of ∠GED = 126° we get,

∠AGE = 126°

∠GEF = 36° and

Q.6: In the Figure, if PQ || ST, ∠PQR = 110° and ∠RST = 130°, find ∠QRS.

First, construct a line XY parallel to PQ.

As we know, the angles on the same side of the transversal are equal to 180°.

So, ∠PQR + ∠QRX = 180°

Or,∠QRX = 180° – 110°

∴ ∠QRX = 70°

∠RST + ∠SRY = 180°

Or, ∠SRY = 180° – 130°

∴ ∠SRY = 50°

Now, for the linear pairs on the line XY-

∠QRX + ∠QRS + ∠SRY = 180°

Substituting their respective values we get,

∠QRS = 180° – 70° – 50°

Or, ∠QRS = 60°

Q.7: In Fig. 6.33, PQ and RS are two mirrors placed parallel to each other. An incident ray AB strikes the mirror PQ at B, the reflected ray moves along the path BC and strikes the mirror RS at C and again reflects back along CD. Prove that AB || CD.

First, draw two lines BE and CF such that BE  ⊥ PQ and CF  ⊥ RS.

Now, since PQ || RS,

So, BE || CF

BE and CF are normals between the incident ray and reflected ray.

As we know,

Angle of incidence = Angle of reflection (By the law of reflection)

∠1 = ∠2 and

We also know that alternate interior angles are equal.

Here, BE ⊥ CF and the transversal line BC cuts them at B and C.

So, ∠2 = ∠3 (As they are alternate interior angles)

Now, ∠1 + ∠2 = ∠3 + ∠4

Or, ∠ABC = ∠DCB

So, AB ∥ CD (alternate interior angles are equal)

Q.8: In Fig. 6.40, ∠X = 62°, ∠XYZ = 54°. If YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively of Δ XYZ, find ∠OZY and ∠YOZ.

As we know, the sum of the interior angles of the triangle is 180°.

So, ∠X +∠XYZ + ∠XZY = 180°

substituting the values as given in the question we get,

62° + 54° + ∠XZY = 180°

Or, ∠XZY = 64°

Now, As we know, ZO is the bisector so,

∠OZY = ½ ∠XZY

∴ ∠OZY = 32°

Similarly, YO is a bisector and so,

∠OYZ = ½ ∠XYZ

Or, ∠OYZ = 27° (As ∠XYZ = 54°)

Now, as the sum of the interior angles of the triangle,

∠OZY +∠OYZ + ∠O = 180°

∠O = 180° – 32° – 27°

Or, ∠O = 121°

Q.9: In the figure, if AB || CD || EF, PQ || RS, ∠RQD = 25° and ∠CQP = 60°, then find ∠QRS.

According to the given figure, we have

AB || CD || EF

If a transversal intersects two parallel lines, then each pair of alternate exterior angles is equal.

Now, since, PQ || RS

⇒ ∠PQC = ∠BRS

We have ∠PQC = 60°

⇒ ∠BRS = 60° … eq.(i)

We also know that,

If a transversal intersects two parallel lines, then each pair of alternate interior angles is equal.

Now again, since, AB || CD

⇒ ∠DQR = ∠QRA

We have ∠DQR = 25°

⇒ ∠QRA = 25° … eq.(ii)

Using linear pair axiom,

∠ARS + ∠BRS = 180°

⇒ ∠ARS = 180° – ∠BRS

⇒ ∠ARS = 180° – 60° (From (i), ∠BRS = 60°)

⇒ ∠ARS = 120° … eq.(iii)

Now, ∠QRS = ∠QRA + ∠ARS

From equations (ii) and (iii), we have,

∠QRA = 25° and ∠ARS = 120°

Hence, the above equation can be written as:

∠QRS = 25° + 120°

⇒ ∠QRS = 145°

Video Lesson on Constructing Angles

Class 9 Maths Chapter 6 Extra Questions

• If two lines intersect, prove that the vertically opposite angles are equal.
• Bisectors of interior ∠B and exterior ∠ACD of a Δ ABC intersect at the point T.Prove that ∠ BTC = ½ ∠ BAC.
• A transversal intersects two parallel lines. Prove that the bisectors of any pair of corresponding angles so formed are parallel.
• In the figure, OD is the bisector of ∠AOC, OE is the bisector of ∠BOC and OD ⊥ OE. Show that the points A, O and B are collinear.

5. The angles of a triangle are in the ratio 5 : 3: 7. The triangle is

• An acute-angled triangle
• An obtuse-angled triangle
• A right triangle
• An isosceles triangle

6. Can a triangle have all angles less than 60°? Give a reason for your answer.

7. Can a triangle have two obtuse angles? Give the reason for your answer.

8. How many triangles can be drawn having its angles as 45°, 64° and 72°? Give the reason for your answer.

9. How many triangles can be drawn having its angles as 53°, 64° and 63°? Give the reason for your answer.

10. Two distinct points in the plane determine a _________________ line.

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doubt in 7 q. how can you prove that if angle 1 and 2 are equal 3 and four are equal? please tell?

they form a ‘z’ that is the shape of alternate interior angles if you look closely so only we conclude it like it

According to the chapter light angle of incidence is equal to angle of reflection. So angle 1 is incidence and 2 reflected ray same for 3 and 4

Just like angle 1 and angle 2, angle 3 is incident ray and angle 4 is reflected ray. CF is normal between them. Therefore, by the law of reflection, angle 3 and angle 4 are equal.

it is based on the law of reflection angle i (incident ray) = angle r (reflected ray).

both the angles are equal as it was formed by an incident ray and a reflected ray and both the ray measures the same ,so if

Incident ray is equal ro reflected ray so /_1 + /_2 = /_3 + /_4 another reason is alternate interior angles

It’s given that the day bisects the angle to form 2 angles. So the two angles are equal. Moreover the incident ray is equal to the reflected ray, so the reflected ray is marked as an incident ray once it comes in contact with the other surface. Hope it helped

How do we do the 3rd question??I am having a doubt

∠POS + ∠ROS + ∠ROQ = 180°    (Linear pair of angles)

Thanks for the questions. It was very useful.

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Class 9th Maths - Coordinate Geometry Case Study Questions and Answers 2022 - 2023

By QB365 on 08 Sep, 2022

QB365 provides a detailed and simple solution for every Possible Case Study Questions in Class 9th Maths Subject - Coordinate Geometry, CBSE. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.

QB365 - Question Bank Software

Coordinate geometry case study questions with answer key.

9th Standard CBSE

Final Semester - June 2015

Mathematics

(b) What are the coordinates of C and D respectively?

(c) What is the distance between B and D?

(d) What is the distance between A and C?

(e) What are the coordinates of the point of intersection of AC and BD?

(ii) What are the coordinates of Police Station?

(iii) Distance between school and police station:

(iv) What are the coordinates of Library?

(v) In which quadrant the point (-1, 4) lies?  

(b) What are the coordinates of A and B respectively?

(c) The coordinates of point O in the sketch -2 is

(d) The point on the y-axis ( in sketch 2) which is equidistant from the points B and C is 

(e) The point on the x-axis ( in sketch 2) which is equidistant from the points C and D is

(b) What are the coordinates of R, taking A as origin?

(c) Side of lawn is :

(d) Shape of lawn is :

(e) Area of lawn is :

(ii) What are the coordinates of position 'D'?

(iii) What are the coordinates of position 'H'?

(iv) In which quadrant, the point 'C' lie?

(v) Find the perpendicular distance of the point E from the y-axis.

*****************************************

Coordinate geometry case study questions with answer key answer keys.

(a) (iii) A(3, 5); B(7, 9) (b) (i) C(11, 5); D(7, 1) (c) (iii) 8 units (d) (iii) 8 units (e) (i) (7, 5)

(i) (b) (2, 3) (ii) (a) (2, -1) (iii) (a) 4 (iv) (d) (6, 2) (v) (b) II

(a) (ii) A(13, 10); B(19, 10) (b) (iv) A(19, 6); B(13, 6) (c) (ii) (16, 8) (d) (i) (0, 8) (e)  (ii) (16, 0)

(a) (iv) C(10, 6) (b) (iii) R(5, 6) (c) (ii)   \(\sqrt{34}\)  units PS 2 = AS 2 + AP 2 = 5 2 + 3 2 = 25 + 9 = 34 ⇒ PS =  \(\sqrt{34}\) (d) (iv) Rhombus (e) (i) 30 sq. units Area of rhombus =  \(1 / 2\)  x product of diagonals =  \(1 / 2\)  x 6 x 10  = 30 sq. units

(i) (d) (-4, 3)  (ii) (b) (-3, -2) (iii) (b) (8, 4.5) (iv) (d) IV (v) (b) 10 units

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• CBSE Sample Papers for Class 9 with Solution 2024-25
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CBSE Sample Question Paper for Class 9 - Free PDF Download

Class 9 is the first step that students take to enter an advanced domain of the academic curriculum. Students follow a stringent curriculum of a set of subjects in Class 9. The conceptual development of students at this level will determine how they perform in the exams. Apart from learning the new concepts in different subjects, one has to get accustomed to the exam pattern as well. They need to use their time studying and practising answering questions properly. To help the students in practising, the subject experts of Vedantu have designed sample question papers for all the subjects. These question papers come with proper solutions for assistance in practising and preparing respective subjects. Once you are done with the entire syllabus of a subject, you can proceed to solve the sample paper by Vedantu and check your progress.

Vedantu is a platform that provides free CBSE Solutions ( NCERT) and other study materials for students. Register Online for Class 9 Science and Class 9 Maths tuition on Vedantu.com to score more marks in your examination.

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Importance of CBSE Class 9 All Subjects Sample Papers with Solutions

There is a list of subjects included in the Class 9 syllabus . Students will have to develop a stringent routine to follow and study all the subjects with the same attention. To make this study time more productive, students often need a set of sample papers apart from the exercise questions to learn how to use the concepts taught to formulate answers.

The sample papers formulated by the experts will be the best to follow and practise. Students will find the ideal ground to check their preparation level by solving these questions at home once a chapter of a subject is done. They will also find sample papers for an entire syllabus of a Class 9 subject here.

These questions are framed by the experts by following the latest syllabus mandated by the CBSE board . The experts have also followed question patterns and trends of the NCERT exercises too. It means that the subject-wise sample papers for Class 9 will help students broaden their preparation and make their answering skills stronger.

Benefits of CBSE Class 9 All Subjects Sample Papers with Solutions

These sample papers have been formulated with the prime aim of delivering an assessment platform. You can test your skills and preparation level by solving the questions in the sample papers. Compare your answers to the solutions and find out which part of the chapters you need to focus on more.

Resolve doubts related to the sample questions framed by using the solutions. You can instantly get the correct answers and the methods to compile them from the solutions and proceed with your preparation.

Focus on how the experts have composed the answers. Learn how to use the concepts and context of a chapter to compile answers and score more in the exams. Uplift your confidence by following the solutions of sample papers while practising.

CBSE Class 9 Sample Papers with Solutions for 2024-25

Cbse sample papers with solutions for class 9.

CBSE Sample Papers for Class 9 - All Subjects

You can not learn to swim by just reading a book. You won’t be able to swim unless and until you get into the water and practice swimming. Similarly, learning all the concepts is not enough until you can write them on paper. For writing answers, you need to practise and hence, the importance of sample question papers for Class 9 CBSE can not be ignored. These sample papers are created by the expert and experienced faculty of the Vedantu. You can avail all the sample papers for Class 9 on the Vedantu platform of all the subjects and start practising them. You will surely see a change in your studies and level of preparation. With these CBSE sample question papers for Class 9 , you can prepare yourself for final exams and can evaluate yourself.

How can you prepare for a subject and check your progress? An exam based on the questions from the syllabus will help you check your level of preparation. This is why the exams are designed and conducted by the schools. Solving question papers will help you get accustomed to the exam pattern. For this, you will need a proper sample paper Class 9 for practising.

Vedantu has come up with the best set of sample papers for all subjects of Class 9 syllabus . These sample papers have been designed following the CBSE guidelines and format so that students can easily find relevance while solving them. The question pattern followed in each subject will reflect in sample paper of Class 9.  

Each subject is handled by a team of expert teachers specialised in that subject. They have studied the CBSE question formats which are followed every year. They have also highlighted the important sections of all the chapters niftily. With this, they have successfully framed the ideal CBSE sample papers for Class 9 for students willing to prepare for the exams.

These sample papers will be the ideal resource for a student preparing for the Class 9 final exams. Once the syllabus of a subject is complete, you can take it forward by solving the sample question papers following the time limit. This is a way to practise solving important questions and following a particular format before an important exam. CBSE Class 9th sample paper can be availed from the website for free. You can test your preparation and answering skills by using this platform and find out your strengths and weaknesses.

Solving a sample paper for Class 9 will also help you gather confidence. You will get a clear idea of how questions are set along with the marks distribution in an exam paper. Why wait then? Get all the sample papers today and check your progress in each subject accordingly.

Why Practise Using CBSE Sample Papers for Class 9?

Apart from the concept development in school and mentoring sessions, you should test your skills on a regular basis. This regular assessment of your knowledge and answering skills will help you discover your level. This is the reason why many students look for sample paper Class 9 for every subject.

Here is a list of reasons for solving sample papers for all subjects in Class 9.

Time Management

One of the prime reasons for solving sample papers is time management. A question paper in the final exam will provide a certain time limit to solve all the questions in it. The ideal way to check your efficiency is by solving sample question papers within the stipulated time period. By practising solving sample papers, you will be able to maintain time efficiently.

Exam Pattern

Every exam has a pattern. The questions are developed and set following that pattern. This is done to help students understand the weightage of every section. They can provide attention to prepare and answer these sections accordingly. By solving a sample paper of Class 9, students will be able to understand the exam pattern and prepare a strategy to score better in the exams. 

Self-Assessment

How can a student assess himself? After solving the exercise questions, there is no platform left to analyse your answering skills and knowledge level. This is where the sample question papers can come in very handy. All the questions in a sample paper have been developed by the expert teachers. Hence, every exam paper will be based on conceptual questions. This is where you can challenge your intellect. Prepare well, solve sample papers and assess your knowledge level.

Finding Weaknesses

When you solve a sample question paper for Class 9 , you will find out your strengths and weaknesses in no time. It is you who can judge your preparation appropriately. Find the weak sections in the syllabus where you need to concentrate and get started. Time is the essence and you have a huge syllabus to complete. Hence, solving sample papers is the best way to ensure a strong preparation for all subjects in the Class 9 syllabus . 

Revision Matters

How can you revise a syllabus nicely? When you solve NCERT sample papers for Class 9 , you will find the best platform for revising the syllabus. Before appearing on a sample test, you go through the entire syllabus once more. Prepare as if it is the final exam and show your skills. 

Merits of Solving Sample Question Paper Class 9

These papers for Class 9 will surely help the students how to answer the questions in exams or how and what kind of questions can be asked and how to deal with them.

They will learn how to manage time in exams and how to complete papers in 3 hours so that they do not leave any questions unanswered.

Students can improve their writing and presentation skills with these papers.

Sample question papers of Class 9 will help the students to evaluate their level of preparation and they can check where they are lacking.

Students will come to know about the exam pattern as well by attempting sample question paper Class 9 CBSE and practising them will boost the confidence level.

Sample Papers for the CBSE Class 9 are available for free download here at Vedantu.

Up to a greater extent, the subjects covered in the CBSE Class 9 serve as the foundation for the students, and it prepares them for Class 10. And therefore, a thorough understanding of the subject is very much required for the students. For having such understanding, it is obvious that they have to study the whole syllabus in a deep manner. But along with that, they have checked their understanding of the same.

For checking the understanding, it is very crucial for the students to solve the questions, but only solving the questions given in the exercise is not going to help the students in scoring good marks in the exam. Because for scoring good marks, the students must need to have the practice of the questions in the same way as it is asked in the real exam.

Hence, to fulfil that requirement of the Class 9 students, Vedantu has prepared the sample question paper to help the students in practising for the exam.

Advantages of Solving the Sample Papers for the Class 9 CBSE Board Subjects

Solving the sample question papers for all of the Class 9 CBSE subjects helps the students in many ways, such as:

Time Management: One of the most crucial aspects of the exam is solving the question at a right time. Because no matter how much have you studied, and how much do you know, if you are unable to solve the questions within a given time, it will not get you the marks. And hence , a good time management skill is required for the students, and this skill can only be learned from practice, which the sample papers can provide.

Boosts the Confidence: The only way the students can boost their confidence is by having enough practice of solving the papers of the exam. And hence , the sample papers for the Class 9 CBSE serves that purpose.

Helps in Finding out the Weak Spot: After solving the question papers, it is important for the students to analyse their progress. And it is in this analysis that the students can examine their complete answers, that is to say, here they can know in which questions they have performed well and in which they have not performed well. In this way, it helps in finding out the weak spots of the subjects.

Features of the CBSE Class 9 Sample Question Papers that Vedantu Provides

It is available in a PDF Format: It is very important for the students to have the question papers available for offline viewing because not all the students have the access to the internet all the time. Also, it must be in such a format that can be accessed on any of the devices, and hence Vedantu provides the sample papers in a PDF file format.

It is Free: All the students of the CBSE Class 9 must have the benefit of solving the sample question paper, and hence Vedantu provides it completely free of cost.

It is Similar to the Real Exam: It is very important for the students to practise the questions which are of the same difficulty level as that of the real exam because only then the students can have a real picture of the exam and of their understanding. Hence, Vedantu provides the students with sample papers that are of the same level as that of the real exam.

Important Study Materials for CBSE Class 9

Download cbse class 9 all subjects sample papers with solutions pdf.

Get the free PDF versions of the sample papers for respective subjects. Check how the experts have compiled the questions and formulated the answers. Develop such skills to broaden your preparation and answering skills. Cover the whole syllabus of a subject and proceed to practise these papers before an exam to complete your preparation.

FAQs on CBSE Sample Papers for Class 9 with Solution 2024-25

1. How to avail Sample Question Paper for Class 9 CBSE?

They are available online on www.vedantu.com for free and students can download them and practise them offline.

2. How to practise these papers?

Revise the syllabus and solve the sample paper with a 3-hour timer and then evaluate yourself by going through the answers.

3. How will these papers help?

These papers are created by the faculty of Vedantu as per the new and latest pattern of CBSE and will surely help you to get better marks in exams.

4. How should I attempt the CBSE Class 9 sample question papers?

You must attempt the question papers in a similar manner that you would attempt the actual exam. Having such a mindset is very important for the students. Therefore, before starting the sample papers, students must first do a revision of the subject, for which you can find the revision notes here: Class 9 Revision Notes, Short Key Notes for CBSE (NCERT) Books (vedantu.com)

5. Why should I download the sample question papers provided by the Vedantu?

You should download the sample question papers provided by the Vedantu for the CBSE Class 9 because at Vedantu you can find the sample papers of not just one but of multiple subjects such as Maths, English Language and Literature, social science, and also many question papers are available for all these subjects, not just one. Also, these question papers are designed in accordance with the syllabus and hence it suits best the 9th Class CBSE students. Furthermore, it is available for free download in a PDF file format.

CBSE Study Materials for Class 9

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